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Class hierarchy can be viewed one of two waysSpecialization (Top Down Approach)Generalization (Bottom Up Approach)SpecializationSpecialization is a process of identifying subsets of an entity that shares different characteristics. It breaks an entity into multiple entities from higher level (super class) to lower level (subclass). The class vehicle can be specialized into Car, Truck and Motorcycle ( Top Down Approach)Hence, vehicle is the superclass and Car, Truck, Motorcycle are subclasses. All three of these inherit attributes from vehicle. Moreover, these three share those attributes among themselves while containing some other attributes which make them different.GeneralizationGeneralization is a process of generalizing an entity which ... Read More
Set the decimal number −int decVal = 40;Now take a variable and set the decVal in it. Find the remainder with 8 since octal has base-8 number system and evaluate it in a loop like the following code snippet.while (quot != 0) { octalVal[i++] = quot % 8; quot = quot / 8; }ExampleYou can try to run the following code to convert decimal to octal number.Live Demousing System; class Demo { public static void Main() { int decVal, quot, i = 1, j; int[] octalVal = new int[80]; ... Read More
You need to check for both the vowels and consonants, but do not forget to check for both the uppercase as well lowercase.For counting vowels, check for “aeiou” characters separately i.e.if (myStr[i] == 'a' || myStr[i] == 'e' || myStr[i] == 'i' || myStr[i] == 'o' || myStr[i] == 'u' || myStr[i] == 'A' || myStr[i] == 'E' || myStr[i] == 'I' || myStr[i] == 'O' || myStr[i] == 'U') { vowel_count++; }For counting consonants, check for other characters in elseif condition −else if ((myStr[i] >= 'a' && myStr[i] = 'A' && myStr[i]
I have added the numbers using an array −int[] num = new int[] {1, 25, 1, 55, 1};Now loop through and find for 1, if 1 is there, 6 then increment the variable that counts the occurrence −foreach(int j in num) { if (j == 1) { cal++; } }ExampleThe following is the code to count the number of 1’s in the entered number.Live Demousing System; public class Demo { public static void Main() { int cal = 0; int[] num = new int[] {1, 25, 1, 55, ... Read More
Firstly, set the string −string str = "Website"; Console.WriteLine("String: "+str);Check for every character in the string and increment a variable that would count the number of occurrences of that character −for (int j = 0; j < str.Length; j++) { if (str[0] == str[j]) { cal++; } }ExampleYou can try to run the following code to count the occurrences of each character.Live Demousing System; public class Demo { public static void Main() { string str = "Website"; Console.WriteLine("String: "+str); while (str.Length > 0) { ... Read More
Let us say the number we have is 12. We have declared and initialized a uint variable by assigning a decimal literal,uint val = 12;The binary representation of 12 is −1100The bits above is 4, therefore to find the total bits, use the Math.log() method −uint res = (uint)Math.Log(val , 2.0) + 1;ExampleYou can try to run the following code to count total bits in a number.Live Demousing System; public class Demo { public static void Main() { uint val = 12; // 1100 in binary uint res = (uint) Math.Log(val, 2.0) + 1; // 1100 has 4 bits Console.WriteLine("Total bits: " + res); } }OutputTotal bits: 4
The number for our example is 11 i.e. binary −1101The total set bits are 3 in 1101; to find it, use a loop till it’s not equal to 0. Here, our num is 11 i.e. decimal −while (num>0) { cal += num & 1; num >>= 1; }ExampleTo count total set bits in a number, use the following code.Live Demousing System; public class Demo { public static void Main() { int cal = 0; // Binary is 1011 int num = 11; while (num>0) { cal += num & 1; num >>= 1; } // 1 bits in 1101 are 3 Console.WriteLine("Total bits: "+cal); } }OutputTotal bits: 3
Firstly, declare the words from 0 to 9 −// words for every digits from 0 to 9 string[] digits_words = { "zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine" };The following are the digits to be converted to words −// number to be converted into words val = 4677; Console.WriteLine("Number: " + val);Use the loop to check for every digit in the given number and convert into words −do { next = val % 10; a[num_digits] = next; num_digits++; val = val / 10; } while(val > 0);ExampleYou can try to ... Read More
Let’ s say you have set the decimal to be −decVal = 34; Console.WriteLine("Decimal: {0}", decVal);Use the ToString() method for the values you get as a binary number for the decimal value −while (decVal >= 1) { val = decVal / 2; a += (decVal % 2).ToString(); decVal = val; }Now set a new empty variable to display the binary number using a loop −string binValue = "";ExampleYou can try to run the following code to convert decimal to binary in C#.Live Demousing System; using System.Collections.Generic; using System.Text; namespace Demo { class MyApplication { ... Read More
Firstly, set the Fahrenheit temperature −double fahrenheit = 97; Console.WriteLine("Fahrenheit: " + fahrenheit);Now convert it into Celsius −celsius = (fahrenheit - 32) * 5 / 9;ExampleYou can try to run the following code to convert Fahrenheit to Celsius.Live Demousing System; using System.Collections.Generic; using System.Linq; using System.Text; namespace Demo { class MyApplication { static void Main(string[] args) { double celsius; double fahrenheit = 97; Console.WriteLine("Fahrenheit: " + fahrenheit); celsius = (fahrenheit - 32) * 5 / 9; Console.WriteLine("Celsius: " + celsius); Console.ReadLine(); } } }OutputFahrenheit: 97 Celsius: 36.1111111111111