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How to extract the names of list elements in R?

Nizamuddin Siddiqui
Nizamuddin Siddiqui
Updated on 11-Mar-2026 3K+ Views

The names of list elements can be extracted by using the names function. For example, if we have a list defined as List that contains three elements with names element1, element2, and element3 then then these names can be extracted from the List by using the below command:names(List)Example1> List1 List1Output$x1 [1] -0.04518909 -0.22779868 0.24339595 -0.86189295 -0.73387277 -0.75313131 [7] 0.39694608 2.30565359 0.55670193 0.21973762 0.62968128 -0.90936921 [13] 1.33946741 -0.16315751 0.31357793 0.40365980 -0.23639612 -2.48749453 [19] 0.52152768 -1.57059863 0.51728464 0.98177111 0.65475629 0.23715538 [25] -0.71796609 -0.42731839 0.32335282 -0.90013122 -0.84549927 -0.88358214 [31] -0.32066379 -0.98945433 0.42469849 -1.63095343 0.32584448 0.10947333 [37] 0.23486625 0.28166351 1.18432843 0.94828212 0.09452671 0.56618262 [43] ...

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Program to find maximum profit by cutting the rod of different length in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 880 Views

Suppose we have a rod is given of length n. We also have a list, that contains different size and price for each size. We have to find the maximum price by cutting the rod and selling them in the market. To get the best price by making a cut at different positions and comparing the prices after cutting the rod.So, if the input is like prices = [1, 5, 8, 9, 10, 17, 17, 20], n = 8, then the output will be 22, as by cutting the rod in length 2 and 6. The profit is 5 + ...

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Count numbers have all 1s together in binary representation in C++

Sunidhi Bansal
Sunidhi Bansal
Updated on 11-Mar-2026 600 Views

We are given a positive integer N. The goal is to count the numbers less than or equal to N that have all 1’s in their binary representation. For example 1 is 1, 3 is 11, 7 is 111, 15 is 1111... so on.If we see the numbers then all of them are 2i-1. Where i start from 1. To check such numbers less than n. We’ll compare if 2i-1

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Count triplet pairs (A, B, C) of points in 2-D space that satisfy the given condition in C++

Sunidhi Bansal
Sunidhi Bansal
Updated on 11-Mar-2026 419 Views

We are given an input of N points on a 2-D space. The goal is to find the count of triplets of points from the input such that one point is the mid-point on the line between the other two. i.e if triplet is (A, B, C) then B is midpoint of A and C ( or any other combination of A, B, C ).We will do this by inserting all points as pairs into a vector. Then add all pairs from this vector in set. By taking two points from the set check if the sum of (x, ...

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Count ways to reach the nth stair using step 1, 2 or 3 in C++

Sunidhi Bansal
Sunidhi Bansal
Updated on 11-Mar-2026 767 Views

We are given a total number of steps in a staircase that is n. A person can reach the next floor by skipping 1, 2 or 3 steps at a time. The goal is to find the number of ways in which the next floor can be reached by doing so.We will use the recursive method by keeping in mind that to reach any i’th step, a person has to jump from i-1th step ( skip 1 step) , i-2th step (skip 2 steps ) or i-3th step ( skip 3 steps ).Let’s understand with examples.Input N=3 stepsOutput Count of ways to ...

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What is the difference between na.omit and complete.cases in R?

Nizamuddin Siddiqui
Nizamuddin Siddiqui
Updated on 11-Mar-2026 1K+ Views

The na.omit function removes all the missing values in a data frame and complete.cases also does the same thing if applied to the whole data frame. The main difference between the two is that complete.cases can be applied to some columns or rows. Check out the below example to understand the difference.ExampleConsider the below data frame:> set.seed(2584) > x y df dfOutput x y 1 NA 25 2 5 5 3 8 NA 4 6 5 5 4 NA 6 4 5 7 6 NA 8 4 NA 9 4 5 10 8 5 11 8 5 12 ...

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Program to rotate a linked list by k places in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 588 Views

Suppose we have a linked list. We have to rotate the list to the right by k places. The value of k will be positive. So if the list is like [1 −> 2 −> 3 −> 4 −> 5 −> NULL], and k = 2, then the output will be [4 −> 5 −> 1 −> 2 −> 3 −> NULL]Let us see the steps −If the list is empty, then return nulllen := 1create one node called tail := headwhile next of tail is not nullincrease len by 1tail := next of tailnext of tail := headk := ...

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Count ways to spell a number with repeated digits in C++

Sunidhi Bansal
Sunidhi Bansal
Updated on 11-Mar-2026 320 Views

We are given a number containing many repeated digits as a string. The goal is to find the number of ways to spell it. For example 112233 can be spelled as double one, double two double three or one one two two three three.We will do this by checking continuous numbers. If the number is “13” there is only one way to spell it as “one three” (20). If digits are “113” ways “double one three”, “one one three” (21). So, the approach is to count the one continuous digit in string and multiply 2(count-1) with the previous result.Let’s understand ...

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Way of validating RadioBoxes with jQuery?

AmitDiwan
AmitDiwan
Updated on 11-Mar-2026 283 Views

Following is how you can validate RadioBoxes with jQuery −ExampleFollowing is the code −            Document           Gender:       Male       Female             isStudent:       yes       No                    var nameValues = 'gen;student'.split(';');    $(function () {       $("form").on("submit", function (ev) {          if (nameValues.filter(val => $(`input[name=${val}]:checked`).length === 0).length > 0) {     ...

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Program to reverse a sentence words stored as character array in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 1K+ Views

Suppose we have one input string sentence where each element is stored as single character, we have to reverse the strings word by word.So, if the input is like ["t", "h", "e", " ", "m", "a", "n", " ", "i", "s", " ", "n", "l", "c", "e"], then the output will be ["n", "l", "c", "e", " ", "i", "s", " ", "m", "a", "n", " ", "t", "h", "e"]To solve this, we will follow these steps −reverse the array sj := 0n := size of sfor initialize i := 0, when i < n, update (increase i by 1), ...

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