Suppose we have a string that is representing a 12-hour clock time with suffix am or pm, and an integer n is also given, we will add n minutes to the time and return the new time in the same format.

So, if the input is like s = "8:20pm" and n = 150, then the output will be 10:50pm

To solve this, we will follow these steps −

• h, m := take the hour and minute part from s

• h := h mod 12

• if the time s is in 'pm', then

• h := h + 12

• t := h * 60 + m + n

• h := quotient of t/60, m := remainder of t/60

• h := h mod 24

• suffix := 'am' if h < 12 otherwise 'pm'

• h := h mod 12

• if h is same as 0, then

• h := 12

• return the time h:m suffix

Let us see the following implementation to get better understanding −

## Example

Live Demo

class Solution:
def solve(self, s, n):
h, m = map(int, s[:-2].split(':'))
h %= 12
if s[-2:] == 'pm':
h += 12
t = h * 60 + m + n
h, m = divmod(t, 60)
h %= 24
suffix = 'a' if h < 12 else 'p'
h %= 12
if h == 0:
h = 12
return "{:02d}:{:02d}{}m".format(h, m, suffix)
ob = Solution()
print(ob.solve("8:20pm", 150))

## Input

"8:20pm", 150

## Output

10:50pm