# Add the occurrence of each number as sublists in Python

We have a list whose elements are numeric. Many elements are present multiple times. We want to create sub list so the frequency of each element along with the elements itself.

## With for and append

In this approach we will compare each element in the list with every other elements after it. If there is a match then count will be incremented and both the element and the count will be made into a subsist. List will be made which should contain subsists showing every element and its frequency.

## Example

Live Demo

def occurrences(list_in):
for i in range(0, len(listA)):
a = 0
row = []
if i not in listB:
for j in range(0, len(listA)):
# matching items from both positions
if listA[i] == listA[j]:
a = a + 1
row.append(listA[i])
row.append(a)
listB.append(row)
# Eliminate repetitive list items
for j in listB:
if j not in list_uniq:
list_uniq.append(j)
return list_uniq
# Caller code
listA = [13,65,78,13,12,13,65]
listB = []
list_uniq = []
print("Number of occurrences of each element in the list:\n")
print(occurrences(listA))

## Output

Running the above code gives us the following result −

Number of occurrences of each element in the list:
[[13, 3], [65, 2], [78, 1], [12, 1]]

## With Counter

We use counter method from the collections module. It will give the count of every element in the list. Then we declare a new empty list and add the key value pair for each item in form of element and its count into the new list.

## Example

Live Demo

from collections import Counter
def occurrences(list_in):
c = Counter(listA)
new_list = []
for k, v in c.items():
new_list.append([k, v])
return new_list
listA = [13,65,78,13,12,13,65]
print("Number of occurrences of each element in the list:\n")
print(occurrences(listA))

## Output

Running the above code gives us the following result −

Number of occurrences of each element in the list:
[[13, 3], [65, 2], [78, 1], [12, 1]]