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What is arrow operator in C++?
The dot and arrow operator are both used in C++ to access the members of a class. They are just used in different scenarios. In C++, types declared as a class, struct, or union are considered "of class type". So the following refers to both of them.
- a.b is only used if b is a member of the object (or reference[1] to an object) a. So for a.b, a will always be an actual object (or a reference to an object) of a class.
- a →b is essentially a shorthand notation for (*a).b, ie, if a is a pointer to an object, then a→b is accessing the property b of the object that points to.
Note that . is not overloadable. → is an overloadable operator, so we can define our own function(operator→()) that should be called when this operator is used. so if a is an object of a class that overloads operator→ (common such types are smart pointers and iterators), then the meaning is whatever the class designer implemented.
[1] References are, semantically, aliases to objects, so I should have added "or reference to a pointer" to the #3 as well. However, I thought this would be more confusing than helpful since references to pointers (T*&) are rarely ever used.
Example
#include<iostream>
class A {
public: int b;
A() { b = 5; }
};
int main() {
A a = A();
A* x = &a;
std::cout << "a.b = " << a.b << "\n";
std::cout << "x->b = " << x->b << "\n";
return 0;
}Output
This will give the output −
5 5
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