How to call a jQuery function after a certain delay?

jQueryWeb DevelopmentFront End Technology

To call a jQuery function after a certain delay, use the siteTimeout() method. Here, jQuery fadeOut() function is called after some seconds.

You can try to run the following code to learn how to work with setTimeout() method in jQuery to call a jQuery function after a delay −

Example

Live Demo

<!DOCTYPE html>
<html>
  <head>
  <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
  <script>
  $(document).ready(function(){
    $("#button1").bind("click",function() {
      setTimeout(function() {
        $('#list').fadeOut();}, 2000);
    });
  });
  </script>
</head>
<body>
  <input type="button" id="button1" value="Fade Out" />
  <br/>
  <br/>
  <div id="list">
   <ul>
     <li>Voice</li>  
     <li>Speak</li>
     <li>Write</li>
   </ul>
  </div>
  <p>The above content will fade out after 2 seconds</p>
</body>
</html>
raja
Published on 31-Jul-2018 18:06:12
Advertisements