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C++ has 5 basic arithematic operators. They are −

- Addition(+)
- Subtraction(-)
- Division(/)
- Multiplication(*)
- Modulo(%)

These operators can operate on any arithmetic operations in C++. Lets have a look at an example −

#include <iostream> using namespace std; main() { int a = 21; int b = 10; int c ; c = a + b; cout << "Line 1 - Value of c is :" << c << endl ; c = a - b; cout << "Line 2 - Value of c is :" << c << endl; c = a * b; cout << "Line 3 - Value of c is :" << c << endl; c = a / b; cout << "Line 4 - Value of c is :" << c << endl; c = a % b; cout << "Line 5 - Value of c is :" << c << endl; return 0; }

This will give the output −

Line 1 - Value of c is :31 Line 2 - Value of c is :11 Line 3 - Value of c is :210 Line 4 - Value of c is :2 Line 5 - Value of c is :1

There are some compound arithmetic operators also available in c++. The compound arithmetic assignment operators are specified in the form e1 op= e2, where e1 is a modifiable l-value not of const type and e2 is one of the following:

- An arithmetic type
- A pointer, if op is + or –

The e1 op= e2 form behaves as e1 = e1 op e2, but e1 is evaluated only once.

The following are the compound arithmatic assignment operators in C++ −

Operators | Description |
---|---|

*= | Multiply the value of the first operand by the value of the second operand; store the result in the object specified by the first operand. |

/= | Multiply the value of the first operand by the value of the second operand; store the result in the object specified by the first operand. |

/= | Divide the value of the first operand by the value of the second operand; store the result in the object specified by the first operand. |

%= | Take modulus of the first operand specified by the value of the second operand; store the result in the object specified by the first operand. |

+= | Add the value of the second operand to the value of the first operand; store the result in the object specified by the first operand. |

–= | Subtract the value of the second operand from the value of the first operand; store the result in the object specified by the first operand. |

Let's have a look at an example using some of these operators −

#include<iostream> using namespace std; int main() { int a = 3, b = 2; a += b; cout << a << endl; a -= b; cout << a << endl; a *= b; cout << a << endl; a /= b; cout << a << endl; return 0; }

This will give the output −

5 3 6 3

Note that Compound assignment to an enumerated type generates an error message. If the left operand is of a pointer type, the right operand must be of a pointer type or it must be a constant expression that evaluates to 0. If the left operand is of an integral type, the right operand must not be of a pointer type.

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