8085 program to count total odd numbers in series of 10 numbers

In this program we will see how to count number of odd numbers in a block of elements.

Problem Statement

Write 8085 Assembly language program to count number of odd numbers in a block of data, where the block size is 10D. The block is starting from location 8000H.

Discussion

The Odd Even checking is very simple. we can determine one number is odd or even by checking only the LSb. When LSb is 1, the number is odd, otherwise it is even. In this program we are taking a number from memory and then ANDing 01H with it. if the result is nonzero, then the number is odd, otherwise it is even.

Input

Address	Data
. . .	. . .
8000	DA
8001	53
8002	26
8003	41
8004	17
8005	AC
8006	78
8007	D8
8008	9C
8009	3F
. . .	. . .

Flow Diagram

Program

Address	HEX Codes	Labels	Mnemonics	Comments
F000	21, 00, 80		LXI H,8000H	Point to the starting byte
F003	0E, 0A		MVI C,0AH	Initialize count to 0AH
F005	06, 00		MVI B, 00H	Clear B register
F007	7E	LOOP	MOV A,M	Load the item from memory
F008	E6, 01		ANI 01H	AND A with 01H
F00A	CA, 0E, F0		JZ SKIP	If Z = 0, jump to skip
F00D	04		INR B	Increase B by 1
F00E	23	SKIP	INX H	Point to next location
F00F	0D		DCR C	Decrease C by 1
F010	C2, 07, F0		JNZ LOOP	if Z = 0, go to loop
F013	78		MOV A,B	Load the count to A
F014	32, 50, 80		STA 8050H	Store the result at 8050H
F017	76		HLT	Terminate the program

Output

Address

Data

8050

Arjun Thakur

Updated on: 30-Jul-2019

1K+ Views

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