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3-6-9 in Python
Suppose we have a number n, we have to construct a list with each number from 1 to n, except when it is multiple of 3 or has a 3, 6, or 9 in the number, it should be the string "no-fill".
So, if the input is like 20, then the output will be ['1', '2', 'clap', '4', '5', 'clap', '7', '8', 'clap', '10', '11', 'clap', 'clap', '14', 'clap', 'clap', '17', 'clap', 'clap', '20']
To solve this, we will follow these steps −
string := "no-fill"
ls:= make a list of numbers as string from 1 to n
for i in range 0 to size of ls - 1, do
if ls[i] is divisible by 3, then
ls[i]:= string
otherwise when '3' is present in ls[i], then
ls[i]:= string
otherwise when '6' is present in ls[i], then
ls[i]:= string
otherwise when '9' is present in ls[i], then
ls[i]:= string
return ls
Let us see the following implementation to get better understanding −
Example
class Solution: def solve(self, n): string = "no-fill" ls=[str(i) for i in range(1,n+1)] for i in range(len(ls)): if int(ls[i])%3==0: ls[i]=string elif '3' in ls[i]: ls[i]=string elif '6' in ls[i]: ls[i]=string elif '9' in ls[i]: ls[i]=string return ls ob = Solution() print(ob.solve(20))
Input
20
Output
['1', '2', 'clap', '4', '5', 'clap', '7', '8', 'clap', '10', '11', 'clap', 'clap', '14', 'clap', 'clap', '17', 'clap', 'clap', '20']
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