# 1's complement notation

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This is one of the methods of representing signed integers in the computer. In this method, the most significant digit (MSD) takes on extra meaning.

• If the MSD is a 0, we can evaluate the number just as we would interpret any normal unsigned integer.
• If the MSD is a 1, this indicates that the number is negative.

The other bits indicate the magnitude (absolute value) of the number.

If the number is negative, then the other bits signify the 1's complement of the magnitude of the number.

Some signed decimal numbers and their equivalent in 1's complement notations are shown below, assuming a word size of 4 bits.

Signed decimal
1’s complement
+6
0110
-6
1001
+0
0000
-0
1111
+7
0111
-7
1000

## Range

From the above table, it is obvious that if the word size is n bits, the range of numbers that can be represented is from -(2n-1- 1) to+(2n-1 -1). A table of word size and the range of 1's complement numbers that can be represented is shown.

Word size
Range for 1's complement numbers
4
-7 to +7
8
-127 to +127
16
-32767 to +32767
32
-2147483647 to +2147483647

## Example 1

Add the numbers (+5) and (-3) using a computer. The numbers are assumed to be represented using 4-bit 1's complement notation.

              1110 <- carry generated during addition              0101 <- (+5) First Number           +  1100 <-(-3) Second Number              0001 <- (+1) Sum

The computer instead of giving the correct answer of +2 = 0010, has given the wrong answer of +1 = 0001! However, to get the correct answer the computer will have to simply add to the result the final carry that is generated, as shown in the following.

   0001 +    1   0010 = (+2) Result


## Example 2

Add the numbers (-4) and (+2) using a computer. The numbers are assumed to be represented using 4-bit 1's complement notation.

              0010 <- carry generated during addition              1011 <- (-4) First Number           +  0010 <-(+2) Second Number              1101 <- (-2) Sum

After the addition of the final array, the result remains as 1101. This is -2, which is the correct answer. In 1 101 the MSB is a 1. It means the number is negative. Then, the remaining bits do not provide the magnitude directly. To solve this problem, just consider 1's complement of 1 101. 1'scomplement of 1 101 is 0 010, which is +2. Thus, 1 101, which is 1'scomplement of 0 010 is −2.