# Write a Golang program to find the element with the minimum value in an array

Go ProgrammingServer Side ProgrammingProgramming

## Examples

• A1 = [2, 4, 6, 7, 8, 10, 3, 6, 0, 1]; Minimum number is 0;
• A2 = [12, 14, 16, 17, 18, 110, 13, 16, 10, 11]; Minimum number is 10;

## Approach to solve this problem

Step 1: Consider the number at the 0th index as the minimum number, min_num = A.

Step 2: Compare min_num with every number in the given array, while iterating.

Step 3: If a number is smaller than min_num, then assign that number to min_num.

Step 4: At the end of iteration, return min_num;

## Program

Live Demo

package main
import "fmt"

func findMinElement(arr []int) int {
min_num := arr

for i:=0; i<len(arr); i++{
if arr[i] < min_num {
min_num = arr[i]
}
}
return min_num
}
func main(){
arr := []int{2, 3, 5, 7, 11, 13}
fmt.Println(findMinElement(arr))
fmt.Println(findMinElement([]int{2, 4, 6, 7, 8, 10, 3, 6, 0, 1}))
fmt.Println(findMinElement([]int{12, 14, 16, 17, 18, 110, 13, 16, 10, 11}))
}

## Output

2
0
10