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Write a C program to maintain cricketer’s information in tabular form using structures
Problem
How to store the cricketer’s data in tabular form in sorted order based on average runs using structures in C Programming language.
Solution
Let’s try to enter the cricketer information such as name, age, no of matches and average runs he scored. It will be entered in the console at runtime using the structure concept.
And try to display the information in tabular form in sorted order based on average runs scored by each person so that it is easy to identify each person's details clearly.
The logic we used to sort the cricketers in ascending order based on average runs they scored is −
for(i=0;i<2;i++){
for(j=i+1;j<2;j++){
if(c[i].avrn > c[j].avrn){
temp1=c[i];
c[i]=c[j];
c[j]=temp1;
}
}
}Program
#include<stdio.h>
#include<conio.h>
#include<string.h>
struct cricketer{
char name[50];
int age;
int match;
float avrn;
char temp;
};
struct cricketer c[20],temp1;
void main() {
int i,j;
for(i=0;i<2;i++){
printf("Enter data of cricketer %d
",i+1);
//fflush(stdin);
printf("Name: ");
gets(c[i].name);
printf("
Age: ");
scanf("%d",&c[i].age);
printf("
Matches: ");
scanf("%d",&c[i].match);
printf("
Average runs: ");
scanf("%f",&c[i].avrn);
scanf("%c",&c[i].temp);
}
/******************/
/* sorting records */
/*******************/
for(i=0;i<2;i++) {
for(j=i+1;j<2;j++) {
if(c[i].avrn > c[j].avrn){
temp1=c[i];
c[i]=c[j];
c[j]=temp1;
}
}
}
printf("Sorted records:
");
for(i=0;i<2;i++){
printf("%d\t%s\t%d\t%d\t%f
",i+1,c[i].name,c[i].age,c[i].match,c[i].avrn);
}
getch();
}Output
Enter data of cricketer 1 Name: Dhoni Age: 39 Matches: 150 Average runs: 200 Enter data of cricketer 2 Name: virat Age: 36 Matches: 135 Average runs: 190 Sorted records: 1 virat 36 135 190.000000 2 Dhoni 39 150 200.000000
Updated on: 05-Mar-2021
5K+ Views
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