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Why is a C++ pure virtual function initialized by 0?
It’s just a syntax, nothing more than that for saying that “the function is pure virtual”.
A pure virtual function is a virtual function in C++ for which we need not to write any function definition and only we have to declare it. It is declared by assigning 0 in declaration.
Here is an example of pure virtual function in C++ program
Example Code
#include<iostream>
using namespace std;
class B {
public: virtual void s() = 0; // Pure Virtual Function
};
class D:public B {
public: void s() {
cout << " Virtual Function in Derived class\n";
}
};
int main() {
B *b;
D dobj;
b = &dobj;
b->s();
}Output
Virtual Function in Derived class
Updated on: 30-Jul-2019
2K+ Views
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