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In this article, we will learn about the solution to the problem statement given below.

**Problem statement** − We are given an integer n, we need to count the number of trailing zeros in the factorial.

Now let’s observe the solution in the implementation below −

# trailing zero def find(n): # Initialize count count = 0 # update Count i = 5 while (n / i>= 1): count += int(n / i) i *= 5 return int(count) # Driver program n = 79 print("Count of trailing 0s "+"in",n,"! is", find(n))

Count of trailing 0s in 79 ! is 18

In this article, we have learned about how we can make a Python Program to Count trailing zeroes in factorial of a number

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