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Validating a square in a 2-D plane in JavaScript
We are required to write a JavaScript function that takes in four arguments. The four arguments will all be arrays of exactly two numbers representing the coordinates of four vertices of a quadrilateral or any figure (closed or unclosed) on a plane.
The task of our function is to determine whether or not the four vertices form a square.
If they do form a square, we should return true, false otherwise.
For example −
If the input coordinates are −
const c1 = [1, 0]; const c2 = [-1, 0]; const c3 = [0, 1]; const c4 = [0, -1];
Then the output should be −
const output = true;
because these coordinates do form a square of area 4 unit sq.
Example
The code for this will be −
const c1 = [1, 0];
const c2 = [-1, 0];
const c3 = [0, 1];
const c4 = [0, -1];
const validSquare = (c1, c2, c3, c4) => {
const dist = (c1, c2) => (Math.sqrt(Math.pow(c1[0] - c2[0],2) + Math.pow(c1[1] - c2[1],2)));
const points = [c1,c2,c3,c4];
let lens = new Set();
for(let i = 0; i < points.length; i++){
for(let j = i + 1; j < points.length; j++){
if(points[i][0] == points[j][0] && points[i][1] == points[j][1]){
return false;
};
let dis = dist(points[i],points[j]);
lens.add(dis)
};
};
return lens.size === 2;
};
console.log(validSquare(c1, c2, c3, c4));Output
And the output in the console will be −
true
Updated on: 26-Feb-2021
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