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Use MongoDB Aggregate and select only top record (descending)
For descending order, use -1, which specifies sorting order for sort(), Let us create a collection with documents −
> db.demo267.insertOne({id:100,"Name":"Chris"}); { "acknowledged" : true, "insertedId" : ObjectId("5e4811951627c0c63e7dbaab") } > db.demo267.insertOne({id:100,"Name":"Adam"}); { "acknowledged" : true, "insertedId" : ObjectId("5e48119e1627c0c63e7dbaac") } > db.demo267.insertOne({id:100,"Name":"David"}); { "acknowledged" : true, "insertedId" : ObjectId("5e4811a51627c0c63e7dbaad") } > db.demo267.insertOne({id:100,"Name":"Bob"}); { "acknowledged" : true, "insertedId" : ObjectId("5e4811ab1627c0c63e7dbaae") }
Display all documents from a collection with the help of find() method −
> db.demo267.find().pretty(); { "_id" : ObjectId("5e4811951627c0c63e7dbaab"), "id" : 100, "Name" : "Chris" } { "_id" : ObjectId("5e48119e1627c0c63e7dbaac"), "id" : 100, "Name" : "Adam" } { "_id" : ObjectId("5e4811a51627c0c63e7dbaad"), "id" : 100, "Name" : "David" } { "_id" : ObjectId("5e4811ab1627c0c63e7dbaae"), "id" : 100, "Name" : "Bob" }
Display all documents from a collection with the help of find() method −
> db.demo267.find().sort({Name:-1}).limit(1);
This will produce the following output −
{ "_id" : ObjectId("5e4811a51627c0c63e7dbaad"), "id" : 100, "Name" : "David" }
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