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Update the records in a table with a specific year fetched from date format like '10/12/2010'?
To update records with a specific year, use the YEAR() method as in the below syntax:
update yourTableName set yourColumnName1=yourValue1 where YEAR(str_to_date(yourColumnName2,'%d/%m/%Y'))=yourValue2;
Let us first create a table −
mysql> create table DemoTable1924 ( UserName varchar(20), UserJoiningDate varchar(40) ); Query OK, 0 rows affected (0.00 sec)
Insert some records in the table using insert command −
mysql> insert into DemoTable1924 values('Chris','10/12/2010');
Query OK, 1 row affected (0.00 sec)
mysql> insert into DemoTable1924 values('David','20/01/2011');
Query OK, 1 row affected (0.00 sec)
mysql> insert into DemoTable1924 values('Mike','20/01/2010');
Query OK, 1 row affected (0.00 sec)
mysql> insert into DemoTable1924 values('Carol','26/04/2013');
Query OK, 1 row affected (0.00 sec)Display all records from the table using select statement −
mysql> select * from DemoTable1924;
This will produce the following output −
+----------+-----------------+ | UserName | UserJoiningDate | +----------+-----------------+ | Chris | 10/12/2010 | | David | 20/01/2011 | | Mike | 20/01/2010 | | Carol | 26/04/2013 | +----------+-----------------+ 4 rows in set (0.00 sec)
Here is the query to update records on the basis of a specific year −
mysql> update DemoTable1924 set UserName='Robert' where YEAR(str_to_date(UserJoiningDate,'%d/%m/%Y'))=2010; Query OK, 2 rows affected (0.00 sec) Rows matched: 2 Changed: 2 Warnings: 0
Let us check the table records once again −
mysql> select * from DemoTable1924;
This will produce the following output −
+----------+-----------------+ | UserName | UserJoiningDate | +----------+-----------------+ | Robert | 10/12/2010 | | David | 20/01/2011 | | Robert | 20/01/2010 | | Carol | 26/04/2013 | +----------+-----------------+ 4 rows in set (0.00 sec)
Updated on: 30-Dec-2019
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