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Update salary field value with 10 percent of each employee in MongoDB
Let us first create a collection with documents −
> db.demo417.insertOne({"EmployeeName":"Chris","EmployeeSalary":500});
{
"acknowledged" : true,
"insertedId" : ObjectId("5e723ebbb912067e57771ae4")
}
> db.demo417.insertOne({"EmployeeName":"Mike","EmployeeSalary":1000});
{
"acknowledged" : true,
"insertedId" : ObjectId("5e723ed7b912067e57771ae5")
}Display all documents from a collection with the help of find() method −
> db.demo417.find();
This will produce the following output −
{ "_id" : ObjectId("5e723ebbb912067e57771ae4"), "EmployeeName" : "Chris", "EmployeeSalary" : 500 }
{ "_id" : ObjectId("5e723ed7b912067e57771ae5"), "EmployeeName" : "Mike", "EmployeeSalary" : 1000 }Following is the query to update salary field value with 10 percent of each employee in employee collection −
> db.demo417.update({ "EmployeeName": { $in: ["Chris", "Mike"] } }, { $mul: { EmployeeSalary: 1.1 }},{multi:true});
WriteResult({ "nMatched" : 2, "nUpserted" : 0, "nModified" : 2 })Display all documents from a collection with the help of find() method −
> db.demo417.find();
This will produce the following output −
{ "_id" : ObjectId("5e723ebbb912067e57771ae4"), "EmployeeName" : "Chris", "EmployeeSalary" : 550 }
{ "_id" : ObjectId("5e723ed7b912067e57771ae5"), "EmployeeName" : "Mike", "EmployeeSalary" : 1100 }
Updated on: 03-Apr-2020
725 Views
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