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Update a MySQL column with JSON format?
To display records like JSON format, use MySQL concat(). Let us first create a table −
mysql> create table DemoTable1373 -> ( -> StudentId int NOT NULL AUTO_INCREMENT PRIMARY KEY, -> StudentDetails text -> ); Query OK, 0 rows affected (0.86 sec)
Insert some records in the table using insert command. Here, we haven’t inserted anything −
mysql> insert into DemoTable1373 values(); Query OK, 1 row affected (0.27 sec) mysql> insert into DemoTable1373 values(); Query OK, 1 row affected (0.08 sec) mysql> insert into DemoTable1373 values(); Query OK, 1 row affected (0.18 sec)
Display all records from the table using select statement −
mysql> select * from DemoTable1373;
This will produce the following output −
+-----------+----------------+ | StudentId | StudentDetails | +-----------+----------------+ | 1 | NULL | | 2 | NULL | | 3 | NULL | +-----------+----------------+ 3 rows in set (0.00 sec)
Following is the query to update a MySQL field with JSON format −
mysql> update DemoTable1373 set StudentDetails=concat("{" "StudentName:", " John ,"," StudentAge:", 21,","," StudentCountryName: "," US","} ");
Query OK, 3 rows affected (0.14 sec)
Rows matched: 3 Changed: 3 Warnings: 0Let us check the table records once again −
mysql> select * from DemoTable1373;
This will produce the following output −
+-----------+---------------------------------------------------------------+
| StudentId | StudentDetails |
+-----------+---------------------------------------------------------------+
| 1 | {StudentName: John , StudentAge:21, StudentCountryName: US} |
| 2 | {StudentName: John , StudentAge:21, StudentCountryName: US} |
| 3 | {StudentName: John , StudentAge:21, StudentCountryName: US} |
+-----------+---------------------------------------------------------------+
3 rows in set (0.00 sec)
Updated on: 11-Nov-2019
828 Views
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