Type.GetInterfaces() Method in C#


The Type.GetInterfaces() method in C# is used to get all the interfaces implemented or inherited by the current Type.

Syntax

Following is the syntax −

public abstract Type[] GetInterfaces ();

Example

Let us now see an example to implement the Type.GetInterfaces() method −

using System;
public class Demo {
   public static void Main(){
      Type type = typeof(float);
      Type myInterface = type.GetInterface("IFormattable",true);
      Type[] myInterfaces = type.GetInterfaces();
      Console.WriteLine("Interface = "+myInterface);
      Console.WriteLine("All the Interfaces...");
      for (int i = 0; i < myInterfaces.Length; i++)
      Console.WriteLine(""+myInterfaces[i]);
   }
}

Output

This will produce the following output −

Interface = System.IFormattable
All the Interfaces...
System.IComparable
System.IFormattable
System.IConvertible
System.IComparable`1[System.Single]
System.IEquatable`1[System.Single]

Example

Let us now see another example to implement the Type.GetInterfaces() method −

using System;
public class Demo {
   public static void Main(){
      Type type = typeof(int);
      Type myInterface = type.GetInterface("IFormattable");
      Type[] myInterfaces = type.GetInterfaces();
      Console.WriteLine("Interface = "+myInterface);
      Console.WriteLine("All the Interfaces...");
      for (int i = 0; i < myInterfaces.Length; i++)
      Console.WriteLine(""+myInterfaces[i]);
   }
}

Output

This will produce the following output −

Interface = System.IFormattable
All the Interfaces...
System.IComparable
System.IFormattable
System.IConvertible
System.IComparable`1[System.Int32]
System.IEquatable`1[System.Int32]
raja
Published on 07-Nov-2019 06:56:51
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