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# Sum of two numbers where one number is represented as array of digits in C++

In this problem, we are given two numbers, from which one is represented using array of digits. Our task is to create a program that will find the sum of two numbers where one number is represented as array of digits.

## Let’s take an example to understand the problem,

Input: n = 213, m[] = {1, 5, 8, } Output: 371 Explanation: 213 + 158 = 371

To solve this problem, we will simply digit by digit from the number which element of the array. It lsb of the number is added to the (n-1)th element of the array. The carry will be propagated for the next sum.

## Example

Program to illustrate the working of our solution,

#include <iostream> using namespace std; void addNumbers(int n, int size, int *m){ int carry = 0; int sum = 0; for(int i = size-1; i >= 0; i--){ sum = (n%10) + m[i] + carry; n /= 10; carry = sum/10; m[i] = sum%10; } } int main() { int n= 679; int m[] = {1, 9, 5, 7, 1, 9}; int size = sizeof(m)/sizeof(m[0]); cout<<"The sum of two numbers where one number is represented as array of digits is "; addNumbers(n, size, m); for(int i = 0; i < size; i++) cout<<m[i]; }

## Output

The sum of two numbers where one number is represented as array of digits is 196398

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