# Sum of the alphabetical values of the characters of a string in C++

In this problem, we are given an array of string str[]. Our task is to find the score of all strings in the array. The score is defined as the product of the position of the string with the sum of the alphabetical values of the characters of the string.

Let’s take an example to understand the problem,

Input

str[] = {“Learn”, “programming”, “tutorials”, “point” }

Explanation

Position of “Learn” − 1 →

sum = 12 + 5 + 1 + 18 + 14 = 50. Score = 50

Position of “programming” − 2 →

sum = 16 + 18 + 15 + 7 + 18 + 1 + 13 + 13 + 9 + 14 + 7 = 131
Score = 262

Position of “tutorials” − 1 →

sum = 20 + 21 + 20 + 15 + 18 + 9 + 1 + 12 +
19 = 135
Score = 405

Position of “point” − 1 →

sum = 16 + 15 + 9 + 14 + 20 = 74
Score = 296

To solve this problem, a simple approach will be iterating over all strings of the array. For each string, store the position and find the sum of alphabetical values of the string. The multiple position and sum and return the product.

## Algorithm

Step 1 − Iterate over the string and store the position and for each string follow step 2 and 3 −

Step 2 − Calculate the sum of the alphabets of the string.

Step 3 − print the product of position and sum.

## Example

Program to illustrate the working of the above solution,

Live Demo

#include <iostream>
using namespace std;
int strScore(string str[], string s, int n, int index){
int score = 0;
for (int j = 0; j < s.length(); j++)
score += s[j] - 'a' + 1;
score *= index;
return score;
}
int main(){
string str[] = { "learn", "programming", "tutorials", "point" };
int n = sizeof(str) / sizeof(str[0]);
string s = str[0];
for(int i = 0; i<n; i++){
s = str[i];
cout<<"The score of string ' "<<str[i]<<" ' is "<<strScore(str, s, n, i+1)<<endl;
}
return 0;
}

## Output

The score of string ' learn ' is 50
The score of string ' programming ' is 262
The score of string ' tutorials ' is 405
The score of string ' point ' is 296

Updated on: 06-Aug-2020

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