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Sum MongoDB Sub-documents field?
You can use aggregate framework for this. Let us first create a collection with documents −
> db.summingSubDocumentDemo.insertOne( ... { "_id" :101, "CustomerDetails" : { "CustomerPurchase" : { "CustomerPurchaseAmount" : 2000 } } }); { "acknowledged" : true, "insertedId" : 101 } > db.summingSubDocumentDemo.insertOne( { "_id" :102, "CustomerDetails" : { "CustomerPurchase" : { "CustomerPurchaseAmount" : 3000 } } }); { "acknowledged" : true, "insertedId" : 102 } > db.summingSubDocumentDemo.insertOne( { "_id" :103, "CustomerDetails" : { "CustomerPurchase" : { "CustomerPurchaseAmount" : 5000 } } }); { "acknowledged" : true, "insertedId" : 103 }
Following is the query to display all documents from a collection with the help of find() method −
> db.summingSubDocumentDemo.find().pretty();
This will produce the following output −
{ "_id" : 101, "CustomerDetails" : { "CustomerPurchase" : { "CustomerPurchaseAmount" : 2000 } } } { "_id" : 102, "CustomerDetails" : { "CustomerPurchase" : { "CustomerPurchaseAmount" : 3000 } } } { "_id" : 103, "CustomerDetails" : { "CustomerPurchase" : { "CustomerPurchaseAmount" : 5000 } } }
Here is the query to sum MongoDB sub-documents fields −
> db.summingSubDocumentDemo.aggregate({$group : {_id: "", ... totalAmount : {$sum: "$CustomerDetails.CustomerPurchase.CustomerPurchaseAmount"}}}, ... {$project: {_id: 0, totalAmount: 1}});
This will produce the following output −
{ "totalAmount" : 10000 }
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