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Subtract the Product and Sum of Digits of an Integer in C++
Suppose we have one number. We have to find the sum of digits and product of digits. After that find the difference between sum and product. So if the number is 5362, then sum is 5 + 3 + 6 + 2 = 16, and 5 * 3 * 6 * 2 = 180. So 180 – 16 = 164
To solve this take each digit and add and multiply one by one, then return the difference.
Example
Let us see the following implementation to get better understanding −
#include <bits/stdc++.h>
using namespace std;
class Solution {
public:
int subtractProductAndSum(int n) {
int prod = 1;
int sum = 0;
for(int t = n;t;t/=10){
sum += t % 10;
prod *= t % 10;
}
return prod - sum;
}
};
main(){
Solution ob;
cout << ob.subtractProductAndSum(5362);
}Input
5362
Output
164
Updated on: 29-Apr-2020
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