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Squared sum of n odd numbers - JavaScript
We are required to write a JavaScript function that takes in a Number, say n, and finds the sum of the square of first n odd natural Numbers.
For example −
If the input number is 3. Then the output will be −
1^2 + 3^2 + 5^2 = 35
Therefore, the output is −
35
Example
Following is the code −
const num = 3; const squaredSum = num => { let sum = 0; for(let i = 1; i <= num; i++){ sum += Math.pow((2 * i) - 1, 2); }; return sum; }; console.log(squaredSum(num));
Output
Following is the output in the console −
35
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