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Sort MongoDB Collection by Array value?
To sort MongoDB collection by Array value, use aggregate() along with $sort. Let us create a collection with documents −
> db.demo577.insertOne(
... {
...
... "student": {
... "details": [
... {
... Name:"Chris",
... Score:45
... },
... {
... Name:"Bob",
... Score:33
... },
... {
... Name:"David",
... Score:48
... }
... ]
... }
... }
... );
{
"acknowledged" : true,
"insertedId" : ObjectId("5e916ff1581e9acd78b427ff")
}
Display all documents from a collection with the help of find() method −
> db.demo577.find();
This will produce the following output −
{ "_id" : ObjectId("5e916ff1581e9acd78b427ff"), "student" : { "details" : [
{ "Name" : "Chris", "Score" : 45 },
{ "Name" : "Bob", "Score" : 33 },
{ "Name" : "David", "Score" : 48 }
] } }
Following is the query to sort the collection by array value −
> db.demo577.aggregate([
... {$unwind:"$student"},
... {$unwind:"$student.details"},
...
... {$sort:{"student.details.Score":-1}}
... ]);
This will produce the following output −
{ "_id" : ObjectId("5e916ff1581e9acd78b427ff"), "student" : { "details" : { "Name" : "David", "Score" : 48 } } }
{ "_id" : ObjectId("5e916ff1581e9acd78b427ff"), "student" : { "details" : { "Name" : "Chris", "Score" : 45 } } }
{ "_id" : ObjectId("5e916ff1581e9acd78b427ff"), "student" : { "details" : { "Name" : "Bob", "Score" : 33 } } }Advertisements