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Sort and Group in one MongoDB aggregation query?
For sorting and grouping in a single query, use the $group operator along with aggregate framework. Let us first create a collection with documents −
> db.sortAndGroupDemo.insertOne({
Price :40,
Product: 10
});
{
"acknowledged" : true,
"insertedId" : ObjectId("5ce8f2bc78f00858fb12e907")
}
> db.sortAndGroupDemo.insertOne({
Price :100,
Product: 10
});
{
"acknowledged" : true,
"insertedId" : ObjectId("5ce8f2bc78f00858fb12e908")
}
> db.sortAndGroupDemo.insertOne({
Price :90,
Product: 20
});
{
"acknowledged" : true,
"insertedId" : ObjectId("5ce8f2bc78f00858fb12e909")
}
> db.sortAndGroupDemo.insertOne({
Price :200,
Product: 10
});
{
"acknowledged" : true,
"insertedId" : ObjectId("5ce8f2bc78f00858fb12e90a")
}
> db.sortAndGroupDemo.insertOne({
Price :70,
Product: 20
});
{
"acknowledged" : true,
"insertedId" : ObjectId("5ce8f2bc78f00858fb12e90b")
}
> db.sortAndGroupDemo.insertOne({
Price :70,
Product: 30
});
{
"acknowledged" : true,
"insertedId" : ObjectId("5ce8f2bd78f00858fb12e90c")
}
Following is the query to display all documents from a collection with the help of find() method −
> db.sortAndGroupDemo.find().pretty();
This will produce the following output −
{
"_id" : ObjectId("5ce8f2bc78f00858fb12e907"),
"Price" : 40,
"Product" : 10
}
{
"_id" : ObjectId("5ce8f2bc78f00858fb12e908"),
"Price" : 100,
"Product" : 10
}
{
"_id" : ObjectId("5ce8f2bc78f00858fb12e909"),
"Price" : 90,
"Product" : 20
}
{
"_id" : ObjectId("5ce8f2bc78f00858fb12e90a"),
"Price" : 200,
"Product" : 10
}
{
"_id" : ObjectId("5ce8f2bc78f00858fb12e90b"),
"Price" : 70,
"Product" : 20
}
{
"_id" : ObjectId("5ce8f2bd78f00858fb12e90c"),
"Price" : 70,
"Product" : 30
}
Following is the query to sort and group in a single MongoDB aggregation query −
> db.sortAndGroupDemo.aggregate(
[
{ "$group": { "_id": "$Product" }},
{ "$sort" : { "Price": 1 }},
{ "$project":{"_id":1 }}
]
);
This will produce the following output −
{ "_id" : 30 }
{ "_id" : 20 }
{ "_id" : 10 }Advertisements