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Sort an Array in C++
Suppose we have an array of integers; we have to sort them in ascending order. So if the array is like [5,2,3,1], then the result will be [1,2,3,5]
To solve this, we will follow these steps −
Make one method called partition, this will take array, low and high
set pivot := low
for i in range low to high – 1
if nums[i] < nums[high], then swap(nums[i] and nums[pivot]), increase pivot by 1
swap nums[pivot] and nums[high]
Define a method called sortArr(), this will take array, low and high
if low >= high, then return
partitionIndex := partition(nums, low, high)
sortArr(nums, low, partitionIndex – 1)
sortArr(nums, partitionIndex + 1, high)
call the sortArr() from main method by passing low and high as 0 and size of arr – 1
Let us see the following implementation to get better understanding −
Example
#include <bits/stdc++.h>
using namespace std;
void print_vector(vector<string> v){
cout << "[";
for(int i = 0; i<v.size(); i++){
cout << v[i] << ", ";
}
cout << "]"<<endl;
}
class Solution {
public:
int partition(vector <int>& nums, int low, int high){
int pivot = low;
for(int i = low; i < high; i++){
if(nums[i] < nums[high]){
swap(nums[i], nums[pivot]);
pivot++;
}
}
swap(nums[pivot], nums[high]);
return pivot;
}
void sortArr(vector <int>& nums, int low, int high){
if(low >= high) return;
int partitionIndex = partition(nums, low, high);
sortArr(nums, low, partitionIndex - 1);
sortArr(nums, partitionIndex + 1, high);
}
vector<int> sortArray(vector<int>& nums) {
sortArr(nums, 0, nums.size() - 1);
return nums;
}
};
main(){
vector<int> v1 = {5,2,3,1};
Solution ob;
print_vector(ob.sortArray(v1));
}Input
[5,2,3,1]
Output
[1,2,3,5]
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