SELECT * WHERE var == [one of many alternatives] in MySQL?
Use IN() for select * where var== [one of many alternatives]. Let us first create a table −
mysql> create table DemoTable1624
-> (
-> ClientId int,
-> ClientName varchar(20)
-> );
Query OK, 0 rows affected (0.39 sec)
Insert some records in the table using insert command −
mysql> insert into DemoTable1624 values(101,'Chris Brown');
Query OK, 1 row affected (0.27 sec)
mysql> insert into DemoTable1624 values(102,'David Miller');
Query OK, 1 row affected (0.18 sec)
mysql> insert into DemoTable1624 values(103,'John Smith');
Query OK, 1 row affected (0.17 sec)
mysql> insert into DemoTable1624 values(104,'Carol Taylor');
Query OK, 1 row affected (0.14 sec)
mysql> insert into DemoTable1624 values(105,'Adam Smith');
Query OK, 1 row affected (0.19 sec)
Display all records from the table using select statement −
mysql> select * from DemoTable1624;
This will produce the following output −
+----------+--------------+
| ClientId | ClientName |
+----------+--------------+
| 101 | Chris Brown |
| 102 | David Miller |
| 103 | John Smith |
| 104 | Carol Taylor |
| 105 | Adam Smith |
+----------+--------------+
5 rows in set (0.00 sec)
Here is the query to implement SELECT * WHERE var == [one of many alternatives] −
mysql> select * from DemoTable1624 where ClientId in(101,102,104);
This will produce the following output −
+----------+--------------+
| ClientId | ClientName |
+----------+--------------+
| 101 | Chris Brown |
| 102 | David Miller |
| 104 | Carol Taylor |
+----------+--------------+
3 rows in set (0.00 sec)
Published on 08-Nov-2019 11:15:50
