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SELECT * WHERE var == [one of many alternatives] in MySQL?
Use IN() for select * where var== [one of many alternatives]. Let us first create a table −
mysql> create table DemoTable1624 -> ( -> ClientId int, -> ClientName varchar(20) -> ); Query OK, 0 rows affected (0.39 sec)
Insert some records in the table using insert command −
mysql> insert into DemoTable1624 values(101,'Chris Brown'); Query OK, 1 row affected (0.27 sec) mysql> insert into DemoTable1624 values(102,'David Miller'); Query OK, 1 row affected (0.18 sec) mysql> insert into DemoTable1624 values(103,'John Smith'); Query OK, 1 row affected (0.17 sec) mysql> insert into DemoTable1624 values(104,'Carol Taylor'); Query OK, 1 row affected (0.14 sec) mysql> insert into DemoTable1624 values(105,'Adam Smith'); Query OK, 1 row affected (0.19 sec)
Display all records from the table using select statement −
mysql> select * from DemoTable1624;
This will produce the following output −
+----------+--------------+ | ClientId | ClientName | +----------+--------------+ | 101 | Chris Brown | | 102 | David Miller | | 103 | John Smith | | 104 | Carol Taylor | | 105 | Adam Smith | +----------+--------------+ 5 rows in set (0.00 sec)
Here is the query to implement SELECT * WHERE var == [one of many alternatives] −
mysql> select * from DemoTable1624 where ClientId in(101,102,104);
This will produce the following output −
+----------+--------------+ | ClientId | ClientName | +----------+--------------+ | 101 | Chris Brown | | 102 | David Miller | | 104 | Carol Taylor | +----------+--------------+ 3 rows in set (0.00 sec)
Updated on: 08-Nov-2019
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