Select total from a MySQL table based on month

For this, you can use GROUP BY MONTH(). Let us first create a table −

mysql> create table DemoTable1628
    -> (
    -> PurchaseDate date,
    -> Amount int
    -> );
Query OK, 0 rows affected (1.55 sec)

Insert some records in the table using insert command.

mysql> insert into DemoTable1628 values('2019-01-10',1500);
Query OK, 1 row affected (0.68 sec)
mysql> insert into DemoTable1628 values('2019-10-10',2000);
Query OK, 1 row affected (0.61 sec)
mysql> insert into DemoTable1628 values('2019-10-24',100);
Query OK, 1 row affected (0.20 sec)
mysql> insert into DemoTable1628 values('2019-11-10',500);
Query OK, 1 row affected (0.17 sec)
mysql> insert into DemoTable1628 values('2019-12-10',1600);
Query OK, 1 row affected (0.32 sec)
mysql> insert into DemoTable1628 values('2019-10-10',900);
Query OK, 1 row affected (0.47 sec)

Display all records from the table using select statement −

mysql> select * from DemoTable1628;

This will produce the following output −

+--------------+--------+
| PurchaseDate | Amount |
+--------------+--------+
| 2019-01-10   |   1500 |
| 2019-10-10   |   2000 |
| 2019-10-24   |    100 |
| 2019-11-10   |    500 |
| 2019-12-10   |   1600 |
| 2019-10-10   |    900 |
+--------------+--------+
6 rows in set (0.00 sec)

Here is the query to get totals from database table based on month −

mysql> select month(PurchaseDate) as Month,year(PurchaseDate) as Year,SUM(Amount)
    -> from DemoTable1628
    -> group by month(PurchaseDate);

This will produce the following output −

+-------+------+-------------+
| Month | Year | SUM(Amount) |
+-------+------+-------------+
|     1 | 2019 |        1500 |
|    10 | 2019 |        3000 |
|    11 | 2019 |         500 |
|    12 | 2019 |        1600 |
+-------+------+-------------+
4 rows in set (0.20 sec)