Select items based on value first, then order on the basis of date for rest of the records in MySQL
Use ORDER BY to fix a record and then display
select * from yourTableName
order by yourColumnName1=yourValue desc,yourColumnName2;
Let us first create a table −
mysql> create table DemoTable1932
(
UserName varchar(20),
ShippingDate date
);
Query OK, 0 rows affected (0.00 sec)
Insert some records in the table using insert command −
mysql> insert into DemoTable1932 values('Chris','2018-10-12');
Query OK, 1 row affected (0.00 sec)
mysql> insert into DemoTable1932 values('David','2019-04-11');
Query OK, 1 row affected (0.00 sec)
mysql> insert into DemoTable1932 values('Mike','2016-12-04');
Query OK, 1 row affected (0.00 sec)
mysql> insert into DemoTable1932 values('Carol','2017-12-26');
Query OK, 1 row affected (0.00 sec)Display all records from the table using select statement −
mysql> select * from DemoTable1932;
This will produce the following output −
+----------+--------------+
| UserName | ShippingDate |
+----------+--------------+
| Chris | 2018-10-12 |
| David | 2019-04-11 |
| Mike | 2016-12-04 |
| Carol | 2017-12-26 |
+----------+--------------+
4 rows in set (0.00 sec)
Here is the query to select items based on value first and then order on the basis of date −
mysql> select * from DemoTable1932
order by UserName='David' desc,ShippingDate;
This will produce the following output −
+----------+--------------+
| UserName | ShippingDate |
+----------+--------------+
| David | 2019-04-11 |
| Mike | 2016-12-04 |
| Carol | 2017-12-26 |
| Chris | 2018-10-12 |
+----------+--------------+
4 rows in set (0.00 sec)
Published on 30-Dec-2019 07:41:53
