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Select items based on value first, then order on the basis of date for rest of the records in MySQL
Use ORDER BY to fix a record and then display
select * from yourTableName order by yourColumnName1=yourValue desc,yourColumnName2;
Let us first create a table −
mysql> create table DemoTable1932 ( UserName varchar(20), ShippingDate date ); Query OK, 0 rows affected (0.00 sec)
Insert some records in the table using insert command −
mysql> insert into DemoTable1932 values('Chris','2018-10-12');
Query OK, 1 row affected (0.00 sec)
mysql> insert into DemoTable1932 values('David','2019-04-11');
Query OK, 1 row affected (0.00 sec)
mysql> insert into DemoTable1932 values('Mike','2016-12-04');
Query OK, 1 row affected (0.00 sec)
mysql> insert into DemoTable1932 values('Carol','2017-12-26');
Query OK, 1 row affected (0.00 sec)Display all records from the table using select statement −
mysql> select * from DemoTable1932;
This will produce the following output −
+----------+--------------+ | UserName | ShippingDate | +----------+--------------+ | Chris | 2018-10-12 | | David | 2019-04-11 | | Mike | 2016-12-04 | | Carol | 2017-12-26 | +----------+--------------+ 4 rows in set (0.00 sec)
Here is the query to select items based on value first and then order on the basis of date −
mysql> select * from DemoTable1932 order by UserName='David' desc,ShippingDate;
This will produce the following output −
+----------+--------------+ | UserName | ShippingDate | +----------+--------------+ | David | 2019-04-11 | | Mike | 2016-12-04 | | Carol | 2017-12-26 | | Chris | 2018-10-12 | +----------+--------------+ 4 rows in set (0.00 sec)
Updated on: 30-Dec-2019
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