Select items based on value first, then order on the basis of date for rest of the records in MySQL

Use ORDER BY to fix a record and then display

select * from yourTableName
order by yourColumnName1=yourValue desc,yourColumnName2;

Let us first create a table −

mysql> create table DemoTable1932
   (
   UserName varchar(20),
   ShippingDate date
   );
Query OK, 0 rows affected (0.00 sec)

Insert some records in the table using insert command −

mysql> insert into DemoTable1932 values('Chris','2018-10-12');
Query OK, 1 row affected (0.00 sec)
mysql> insert into DemoTable1932 values('David','2019-04-11');
Query OK, 1 row affected (0.00 sec)
mysql> insert into DemoTable1932 values('Mike','2016-12-04');
Query OK, 1 row affected (0.00 sec)
mysql> insert into DemoTable1932 values('Carol','2017-12-26');
Query OK, 1 row affected (0.00 sec)

Display all records from the table using select statement −

mysql> select * from DemoTable1932;

This will produce the following output −

+----------+--------------+
| UserName | ShippingDate |
+----------+--------------+
| Chris    | 2018-10-12   |
| David    | 2019-04-11   |
| Mike     | 2016-12-04   |
| Carol    | 2017-12-26   |
+----------+--------------+
4 rows in set (0.00 sec)

Here is the query to select items based on value first and then order on the basis of date −

mysql> select * from DemoTable1932
    order by UserName='David' desc,ShippingDate;

This will produce the following output −

+----------+--------------+
| UserName | ShippingDate |
+----------+--------------+
| David    | 2019-04-11   |
| Mike     | 2016-12-04   |
| Carol    | 2017-12-26   |
| Chris    | 2018-10-12   |
+----------+--------------+
4 rows in set (0.00 sec)