Select count of values (Yes, No) with same ids but different corresponding records in MySQL?
For this, you can use SUM() along with CASE statement. Let us first create a −
mysql> create table DemoTable1430
-> (
-> EmployeeId int,
-> isMarried ENUM('YES','NO')
-> );
Query OK, 0 rows affected (0.60 sec)Insert some records in the table using insert −
mysql> insert into DemoTable1430 values(1001,'Yes');
Query OK, 1 row affected (0.19 sec)
mysql> insert into DemoTable1430 values(1001,'No');
Query OK, 1 row affected (0.12 sec)
mysql> insert into DemoTable1430 values(1001,'Yes');
Query OK, 1 row affected (0.09 sec)
mysql> insert into DemoTable1430 values(1001,'Yes');
Query OK, 1 row affected (0.16 sec)
Display all records from the table using select −
mysql> select * from DemoTable1430;
This will produce the following output −
+------------+-----------+
| EmployeeId | isMarried |
+------------+-----------+
| 1001 | YES |
| 1001 | NO |
| 1001 | YES |
| 1001 | YES |
+------------+-----------+
4 rows in set (0.00 sec)
Here is the query to select count of value (Yes, No) −
mysql> select EmployeeId,sum(isMarried='Yes') as NumberOfMarried,
-> sum(isMarried='No') as NumberOfUnMarried
-> from DemoTable1430
-> group by EmployeeId;
This will produce the following output −
+------------+-----------------+-------------------+
| EmployeeId | NumberOfMarried | NumberOfUnMarried |
+------------+-----------------+-------------------+
| 1001 | 3 | 1 |
+------------+-----------------+-------------------+
1 row in set (0.00 sec)
Published on 12-Nov-2019 10:56:18
