Select count of values (Yes, No) with same ids but different corresponding records in MySQL?

For this, you can use SUM() along with CASE statement. Let us first create a −

mysql> create table DemoTable1430
   -> (
   -> EmployeeId int,
   -> isMarried ENUM('YES','NO')
   -> );
Query OK, 0 rows affected (0.60 sec)

Insert some records in the table using insert −

mysql> insert into DemoTable1430 values(1001,'Yes');
Query OK, 1 row affected (0.19 sec)
mysql> insert into DemoTable1430 values(1001,'No');
Query OK, 1 row affected (0.12 sec)
mysql> insert into DemoTable1430 values(1001,'Yes');
Query OK, 1 row affected (0.09 sec)
mysql> insert into DemoTable1430 values(1001,'Yes');
Query OK, 1 row affected (0.16 sec)

Display all records from the table using select −

mysql> select * from DemoTable1430;

This will produce the following output −

+------------+-----------+
| EmployeeId | isMarried |
+------------+-----------+
|       1001 | YES       |
|       1001 | NO        |
|       1001 | YES       |
|       1001 | YES       |
+------------+-----------+
4 rows in set (0.00 sec)

Here is the query to select count of value (Yes, No) −

mysql> select EmployeeId,sum(isMarried='Yes') as NumberOfMarried,
   -> sum(isMarried='No') as NumberOfUnMarried
   -> from DemoTable1430
   -> group by EmployeeId;

This will produce the following output −

+------------+-----------------+-------------------+
| EmployeeId | NumberOfMarried | NumberOfUnMarried |
+------------+-----------------+-------------------+
|       1001 |               3 |                 1 |
+------------+-----------------+-------------------+
1 row in set (0.00 sec)