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SecureRandom nextBytes() method in Java
The number of random bytes as specified by the user can be obtained using the nextBytes() method in the class java.security.SecureRandom. This method requires a single parameter i.e. a random byte array and it returns the random bytes as specified by the user.
A program that demonstrates this is given as follows −
Example
import java.security.*;
import java.util.*;
public class Demo {
public static void main(String[] argv) {
try {
SecureRandom sRandom = SecureRandom.getInstance("SHA1PRNG");
String s = "Apple";
byte[] arrB = s.getBytes();
System.out.println("The Byte array before the operation is: " + Arrays.toString(arrB));
sRandom.nextBytes(arrB);
System.out.println("The Byte array after the operation is: " + Arrays.toString(arrB));
} catch (NoSuchAlgorithmException e) {
System.out.println("Error!!! NoSuchAlgorithmException");
} catch (ProviderException e) {
System.out.println("Error!!! ProviderException");
}
}
}Output
The Byte array before the operation is: [65, 112, 112, 108, 101] The Byte array after the operation is: [110, -119, -65, -84, 54]
Now let us understand the above program.
The nextBytes() method is used to obtain the number of random bytes as specified by the user.
Using this, the byte array before and after the operation is displayed. A code snippet that demonstrates is given as follows −
try {
SecureRandom sRandom = SecureRandom.getInstance("SHA1PRNG");
String s = "Apple";
byte[] arrB = s.getBytes();
System.out.println("The Byte array before the operation is: " + Arrays.toString(arrB));
sRandom.nextBytes(arrB);
System.out.println("The Byte array after the operation is: " + Arrays.toString(arrB));
}
Updated on: 30-Jul-2019
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