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Search elements in a sorted object array in Java
An element can be searched in a sorted object array in Java by using the method
java.util.Arrays.binarySearch(). This method returns the index of the required element if it is available in the array, otherwise it returns (-(insertion point) - 1) where the insertion point is the position at which the element would be inserted into the array. A program that searches the required element in a sorted object array is given as follows −
Example
import java.util.Arrays;
public class Demo {
public static void main(String[] args) {
String str[] = { "P", "M", "A", "T", "D"};
Arrays.sort(str);
System.out.println("The sorted array of strings is: ");
for (String i : str) {
System.out.println(i);
}
int pos = Arrays.binarySearch(str, "M");
System.out.println("The element M is at index: " + pos);
}
}Output
The sorted array of strings is: A D M P T The element M is at index: 2
Now let us understand the above program.
The elements of str are sorted using Arrays.sort() method. Then the sorted string array is printed using for loop. A code snippet which demonstrates this is as follows −
String str[] = { "P", "M", "A", "T", "D"};
Arrays.sort(str);
System.out.println("The sorted array of strings is: ");
for (String i : str) {
System.out.println(i);
}The method Arrays.binarySearch() is used to find the index of element “M”. Then this is displayed. A code snippet which demonstrates this is as follows −
int pos = Arrays.binarySearch(str, "M");
System.out.println("The element M is at index: " + pos);
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