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Reverse the words in the string that have an odd number of characters in JavaScript
We are required to write a JavaScript function that takes in a string and reverses the words in the string that have an odd number of characters in them.
Any substring in the string qualifies to be a word, if either it is encapsulated by two spaces on either ends or present at the end or beginning and followed or preceded by a space.
Example
The code for this will be −
const str = 'hello world, how are you';
const idOdd = str => str.length % 2 === 1;
const reverseOddWords = (str = '') => {
const strArr = str.split(' ');
return strArr.reduce((acc, val) => {
if(idOdd(val)){
acc.push(val.split('').reverse().join(''));
return acc;
};
acc.push(val);
return acc;
}, []).join(' ');
};
console.log(reverseOddWords(str));Output
Following is the output on console −
olleh world, woh era uoy
Updated on: 10-Oct-2020
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