# Returning a range or a number that specifies the square root of a number in JavaScript

## Problem

We are required to write a JavaScript function that takes in an integer n and returns either −

• an integer k if n is a square number, such that k * k == n or
• a range (k, k+1), such that k * k < n and n < (k+1) * (k+1).

## Example

Following is the code −

Live Demo

const num = 83;
const squareRootRange = (num = 1) => {
const exact = Math.sqrt(num);
if(exact === Math.floor(exact)){
return exact;
}else{
return [Math.floor(exact), Math.ceil(exact)];
};
};
console.log(squareRootRange(num));

## Output

Following is the console output −

[9, 10]