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Reshaping 2-D array in JavaScript
Problem
We are required to write a JavaScript function that takes in a 2-D array of numbers, arr, as the first argument and two numbers, r and c, representing the row number and column number of the desired matrix, respectively.
Our function should form and return a new 2-D array with the specified rows and columns in the same row-traversing order as they were in the input array.
For example, if the input to the function is −
const arr = [ [6, 7], [8, 9] ]; const r = 1, c = 4;
Then the output should be −
const output = [[6, 7, 8, 9]];
Output Explanation
The row-traversing of arr is [6, 7, 8, 9]. The new reshaped matrix is a 1 * 4 matrix, fill it row by row by using the previous list
Example
Following is the code −
const arr = [
[6, 7],
[8, 9]
];
const r = 1, c = 4;
const reshapeArray = (arr, r, c) => {
if (r * c !== arr.length * arr[0].length) {
return arr
}
const res = []
let row = []
arr.forEach(items => items.forEach((num) => {
row.push(num)
if (row.length === c) {
res.push(row)
row = []
}
}))
return res
};
console.log(reshapeArray(arr, r, c));Output
Following is the console output −
[[6, 7, 8, 9]]
Updated on: 21-Apr-2021
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