# Reshape the Matrix in C++

C++Server Side ProgrammingProgramming

In different platform there is very useful function called 'reshape', that function is used to reshape a matrix into a new one with different size but data will be same. So, if we have a matrix and two values r and c for the row number and column number of the wanted reshaped matrix, respectively.

So, if the input is like [[5,10],[15,20]], row = 1 and col = 4, then the output will be [[5, 10, 15, 20]]

To solve this, we will follow these steps−

• Define an array temp

• Define one 2D array res of size (r x c)

• count := 0

• for initialize i := 0, when i < size of nums, update (increase i by 1), do −

• for initialize j := 0, when j < size of nums, update (increase j by 1), do −

• insert nums[i, j] at the end of temp

• if r * c is not equal to size of nums, then −

• return nums

• for initialize i := 0, when i < r, update (increase i by 1), do −

• for initialize j := 0, when j < c, update (increase j by 1), do −

• count = count + 1

• res[i, j] := temp[count]

• return res

## Example

Let us see the following implementation to get better understanding −

Live Demo

#include <bits/stdc++.h>
using namespace std;
void print_vector(vector<vector<auto>> v){
cout << "[";
for(int i = 0; i<v.size(); i++){
cout << "[";
for(int j = 0; j <v[i].size(); j++){
cout << v[i][j] << ", ";
}
cout << "],";
}
cout << "]"<<endl;
}
class Solution {
public:
vector<vector<int>> matrixReshape(vector<vector<int>>& nums, int r, int c) {
vector<int> temp;
vector<vector<int> > res(r, vector<int>(c));
int count = 0;
for (int i = 0; i < nums.size(); i++) {
for (int j = 0; j < nums.size(); j++) {
temp.push_back(nums[i][j]);
}
}
if (r * c != nums.size() * nums.size())
return nums;
for (int i = 0; i < r; i++) {
for (int j = 0; j < c; j++) {
res[i][j] = temp[count++];
}
}
return res;
}
};
main(){
Solution ob;
vector<vector<int>> v = {{5,10},{15,20}};
print_vector(ob.matrixReshape(v, 1, 4));
}

## Input

{{5,10},{15,20}}, 1, 4

## Output

[[5, 10, 15, 20, ],]