Regular Expression "S" Metacharacter in Java

The subexpression/metacharacter “\S” matches the non-white space characters.

Example 1

import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class RegexExample {
   public static void main( String args[] ) {
      String regex = "\S";
      String input = "Hello how are you welcome to Tutorialspoint !";
      Pattern p = Pattern.compile(regex);
      Matcher m = p.matcher(input);
      int count = 0;
      while(m.find()) {
         count++;
      }
      System.out.println("Number of matches: "+count);
   }
}

Output

Number of matches: 38

Example 2

import java.util.Scanner;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Example {
   public static void main( String args[] ) {
      String regex = "\S";
      Scanner sc = new Scanner(System.in);
      System.out.println("Enter 5 input strings: ");
      String input[] = new String[5];
      for (int i=0; i<5; i++) {
         input[i] = sc.nextLine();
      }
      //Creating a Pattern object
      Pattern p = Pattern.compile(regex);
      System.out.println("Number of characters in each string w/o spaces: ");
      for(int i=0; i<5;i++) {
         //Creating a Matcher object
         Matcher m = p.matcher(input[i]);
         int count = 0;
         while(m.find()) {
            count++;
         }
         System.out.println("String "+i+": "+count);
      }
   }
}

Output

Enter 5 input strings:
sample123
test data
test *123
ab bc cd de
hello how are you welcome to Tutorialspoint
Number of characters in each string w/o spaces:
String 0: 9
String 1: 8
String 2: 8
String 3: 8
String 4: 37