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Regular Expression "S" Metacharacter in Java
The subexpression/metacharacter “\S” matches the non-white space characters.
Example 1
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class RegexExample {
public static void main( String args[] ) {
String regex = "\S";
String input = "Hello how are you welcome to Tutorialspoint !";
Pattern p = Pattern.compile(regex);
Matcher m = p.matcher(input);
int count = 0;
while(m.find()) {
count++;
}
System.out.println("Number of matches: "+count);
}
}Output
Number of matches: 38
Example 2
import java.util.Scanner;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Example {
public static void main( String args[] ) {
String regex = "\S";
Scanner sc = new Scanner(System.in);
System.out.println("Enter 5 input strings: ");
String input[] = new String[5];
for (int i=0; i<5; i++) {
input[i] = sc.nextLine();
}
//Creating a Pattern object
Pattern p = Pattern.compile(regex);
System.out.println("Number of characters in each string w/o spaces: ");
for(int i=0; i<5;i++) {
//Creating a Matcher object
Matcher m = p.matcher(input[i]);
int count = 0;
while(m.find()) {
count++;
}
System.out.println("String "+i+": "+count);
}
}
}Output
Enter 5 input strings: sample123 test data test *123 ab bc cd de hello how are you welcome to Tutorialspoint Number of characters in each string w/o spaces: String 0: 9 String 1: 8 String 2: 8 String 3: 8 String 4: 37
Updated on: 19-Nov-2019
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