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# Race Car in C++

Suppose we have a car, that starts at position 0 and speed +1 on an infinite number line. The car runs automatically according to a sequence of instructions A: for accelerate and R − for reverse. When we get an instruction "A", our car does the following −

- position := position + speed, then speed = speed * 2.

When we get an instruction "R", our car does the following −

- if speed is positive then speed = -1,
- otherwise speed = 1.

For example, after executing the instructions "AAR", our car goes to positions 0->1->3->3, and speed goes to 1->2->4->-1.

Now suppose we have some target position; we have to find the length of the shortest sequence of instructions to get there.

So, if the input is like target = 6, then the output will be 5 as one of the possible sequence is AAARA, the position sequence will be 0->1->3->7->7->6

To solve this, we will follow these steps −

- Define one set visited
- Define one queue q
- insert { 0, 1 } into q
- for initialize level := 0, when not q is empty, update (increase level by 1), do −
- for initialize k := size of q, when k > 0, update (decrease k by 1), do −
- Define one pair curr := front element of q, delete element from q
- if first of curr is same as target, then −
- return level

- forward := first of curr + second of curr
- forwardSpeed := second of curr * 2
- key := convert forward to string concatenate " * " concatenate convert forwardSpeed to string
- if forward > 0 and |forward - target| < target and not key is not in visited, then −
- insert key into visited
- insert { forward, forwardSpeed } into q

- key := convert first of curr to string concatenate " * " concatenate 0 when second of curr > 0, otherwise -1
- if curr.first > 0 and |target - curr.first| < target and key is not in visited, then −
- insert key into visited
- insert { curr.first, (if curr.second > 0, then -1, otherwise 1 }) into q

- for initialize k := size of q, when k > 0, update (decrease k by 1), do −
- return -1

Let us see the following implementation to get better understanding −

## Example

#include <bits/stdc++.h> using namespace std; class Solution { public: int racecar(int target) { unordered_set < string > visited; queue < pair <int ,int> > q; q. push({0, 1}); for(int level = 0; !q.empty(); level++){ for(int k = q.size(); k > 0; k-- ){ pair <int, int> curr = q.front(); q.pop(); if(curr.first == target) return level; int forward = curr.first + curr.second; int forwardSpeed = curr.second * 2; string key = to_string(forward) + "*" + to_string(forwardSpeed); if(forward > 0 && abs(forward - target) < target && !visited.count(key)){ visited.insert(key); q.push({forward, forwardSpeed}); } key = to_string(curr.first) + "*" + to_string(curr.second > 0 ? - 1: 1); if(curr.first > 0 && abs(target - curr.first) < target && !visited.count(key)){ visited.insert(key); q.push({curr.first, curr.second > 0 ? - 1: 1}); } } } return -1; } }; main(){ Solution ob; cout << (ob.racecar(6)); }

## Input

6

## Output

5

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