# Program to find the count of coins of each type from the given ratio in C++

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In this problem, we are given four numbers that define the totalPrice and the ratio of coins of 1 Rs, 50 paise, 25 paise in the bag. Our task is to create a program to find the count of coins of each type from the given ratio in C++.

Code description − Here, we need to use the coins of 1 Rs, 50 paise, and 25 paise from the bag to give the total sum of coins to the given total.

Let’s take an example to understand the problem,

## Input

TotalPrice = 225, 1Rs = 2, 50P = 3, 25P = 4

## Output

1 Rs coin = 100
50 P coin = 150
25 P coin = 200

## Explanation

Considering the ratio, the value of coins that make up the value.

1 RE coin 2X,
50 paise coin 1.5X,
25 paise coin 1X,

Summing up all values = 225

2X + 1.5X + 1X = 225
4.5X = 225 => X = 225/4.5 = 50,

Value of 1Re coins = 100, coins 100

Value of 50 paise coins = 75, coins 150

Value of 25 paise coins = 50, coins 200

## Solution Approach

As in the explanation, we will find the amount contributed by each coin to the sum. And then find the number of coins each value based on the value. For 1 Re coins, X is the number of coins.

For 50 paise coins, 2X is the number of coins.

For 25 paise coins, 4X is the number of coins.

Program to illustrate the working of our solution,

## Example

Live Demo

#include <iostream>
using namespace std;
int CalcCoinValue(int totalPrice, int re1, int p50, int p25) {
float val1Coin = (re1 * 1.0), val50pCoin = (p50/2.0), val25pCoin =(p25/4.0);
int result = totalPrice / (val1Coin + val50pCoin + val25pCoin);
return result;
}
int main() {
int totalPrice = 225;
int re1 = 2, p50 = 3, p25 = 4;
int coinValue = CalcCoinValue(totalPrice, re1, p50, p25);
cout<<"Count of 1 rupee coin = " <<(coinValue * re1)<<endl;
cout<<"Count of 50 paise coin = " <<(coinValue * p50)<<endl;
cout<<"Count of 25 paise coin = " <<(coinValue * p25)<<endl;
return 0;
}

## Output

Count of 1 rupee coin = 100
Count of 50 paise coin = 150
Count of 25 paise coin = 200
Updated on 16-Sep-2020 08:57:48