Program to find the common ratio of three numbers in C++
In this problem, we are given two ratios i.e. x:y and y:z. Our task is to create a Program to find the common ratio of three numbers in C++.
Problem Description − We need to find the common ratio of three numbers using the ratios given to us. Using x:y and y:z, we will find x:y:z.
Let’s take an example to understand the problem,
Input
3:5 8:9
Output
24: 40: 45
Explanation − We have x:y and y:z, two different ratios. To create x:y:z, we will make y same in both ratios that will make the ratio possible. To do so, we will cross multiply.
$\frac{\square}{\square1}
=\frac{\square2}{\square}\Rightarrow\frac{\square\square2}{\square1\square2}=\frac{\square1\square2}{\square2\square}$
This will make the ratio x’:y’:z’
So, 3*8 : 8*5 : 5*9 = 24 : 40 : 45 is the ratio.
Solution Approach
As discussed in the above example, we need to make the middle element common for both the ratios. And for this, we will do cross-multiplication but sometimes cross multiplication might make the result larger. So, an efficient approach would be to find the LCM. And then finding the ratio as −
$\frac{\square*\square\square\square}{\square1}:\square\square\square:\frac{\square*\square\square\square}{\square2}$
Program to illustrate the working of our solution,
Example
Live Demo
#include <iostream>
using namespace std;
int calcLcm(int a, int b){
int lcm = 2;
while(lcm <= a*b) {
if( lcm%a==0 && lcm%b==0 ) {
return lcm;
break;
}
lcm++;
}
return 0;
}
void calcThreeProportion(int x, int y1, int y2, int z){
int lcm = calcLcm(y1, y2);
cout<<((x*lcm)/y1)<<" : "<<lcm<<" : "<<((z*lcm)/y2);
}
int main() {
int x = 12, y1 = 15, y2 = 9, z = 16;
cout<<"The ratios are\t"<<" x:y = "<<x<<":"<<y1<<"\ty:z = "<<y2<<":"<<z<<endl;
cout<<"The common ratio of three numbers is\t";
calcThreeProportion(x, y1, y2, z);
return 0;
}Output
The ratios are x:y = 12:15 y:z = 9:16
The common ratio of three numbers is 36 : 45 : 80
Published on 02-Jun-2020 11:42:34
