Program to find sum of medians of all odd length sublists in C++

Suppose we have a list of numbers called nums, we have to find the sum of the medians of every odd−length sublist of the given list.

So, if the input is like nums = [2, 4, 6, 3], then the output will be 23, as the odd−length sublists are − [2], [4], [6], [3], [2, 4, 6], [4, 6, 3], so the sum of the medians is 2 + 4 + 6 + 3 + 4 + 4 = 23

To solve this, we will follow these steps −

• ret := 0

• for initialize i := 0, when i < size of nums, update (increase i by 1), do −

  • define priority queue called que_max

  • define another priority queue called que_min

  • for initialize j := i, when j < size of nums, update (increase j by 1), do −

    • insert nums[j] into que_max

    • while size of que_max >= 2, do −

      • insert top element of que_max into que_min

      • delete top element from que_max

    • while (size of que_min is not 0 and top element of que_max > top element of que_min), do −

      • a := top element of que_max, delete top element from que_max

      • b := top element of que_min, delete top element from que_min

      • insert b into que_max

      • insert a into que_min

    • if i mod 2 is same as j mod 2, then −

      • ret := ret + top element of que_max

• return ret

Let us see the following implementation to get better understanding −

Example

 Live Demo

#include <bits/stdc++.h>
using namespace std;
int solve(vector<int>& nums) {
   int ret = 0;
   for (int i = 0; i < nums.size(); i++) {
      priority_queue<int> que_max;
      priority_queue<int, vector<int>, greater<int>> que_min;
      for (int j = i; j < nums.size(); j++) {
         que_max.push(nums[j]);
         while (que_max.size() - que_min.size() >= 2) {
            que_min.push(que_max.top());
            que_max.pop();
         }
         while (que_min.size() && que_max.top() > que_min.top()) {
            int a = que_max.top();
            que_max.pop();
            int b = que_min.top();
            que_min.pop();
            que_max.push(b);
            que_min.push(a);
         }
         if (i % 2 == j % 2) {
            ret += que_max.top();
         }
      }
   }
   return ret;
}
int main(){
   vector<int> v = {2, 4, 6, 3};
   cout << solve(v);
}

Input

{2, 4, 6, 3}

Output

23

Arnab Chakraborty

Published on 25-Dec-2020 05:44:08

• Related Questions & Answers
• Program to find sum of all odd length subarrays in Python
• Program to find sum of the sum of all contiguous sublists in Python
• Sum of All Possible Odd Length Subarrays in JavaScript
• Program to find minimum largest sum of k sublists in C++
• Program to find sum of k non-overlapping sublists whose sum is maximum in C++
• C# program to print all sublists of a list
• Program to find largest sum of 3 non-overlapping sublists of same sum in Python
• C Program for Find sum of odd factors of a number?
• C++ program for Find sum of odd factors of a number
• Program to find maximum sum of two non-overlapping sublists in Python
• C++ Program to find minimal sum of all MEX of substrings
• Program to find number of sublists whose sum is given target in python
• Python program to find the sum of all even and odd digits of an integer list
• Python program to print all sublists of a list.
• Program to find the sum of the lengths of two nonoverlapping sublists whose sum is given in Python