Program to find angle between hour and minute hands of a clock in C++?

Suppose we have two values hours and minutes. We have to find a smaller angle formed between the hour and the minute hand.

So, if the input is like hour = 12 minutes = 45, then the output will be 112.5

To solve this, we will follow these steps:

• if h = 12, then set h := 0

• if m = 60, then set m := 0

• hAngle := 0.5 * (60h) + m

• mAngle := 6m

• ret := |hAngle - mAngle|

return minimum of ret and (360 – ret)Let us see the following implementation to get better understanding:

Example

 Live Demo

#include <bits/stdc++.h>
using namespace std;
class Solution {
public:
   double solve(int h, int m) {
      if(h == 12) h = 0;
      if(m == 60) m = 0;
      double hAngle = 0.5*((60 * h) + m);
      double mAngle = 6 * m;
      double ret = abs(hAngle - mAngle);
      return min(360 - ret, ret);
   }
};
main(){
   Solution ob;
   cout << (ob.solve(12, 45));
}

Input

12, 45

Output

112.5