# Program to Add Two Complex Numbers in C

CServer Side ProgrammingProgramming

Given are the two complex numbers in the form of a1+ ib1 and a2 + ib2, the task is to add these two complex numbers.

Complex numbers are those numbers which can be expressed in the form of “a+ib” where “a” and “b” are the real numbers and i is the imaginary number which is the solution of the expression 𝑥 2 = −1 as no real number satisfies the equation that’s why it is called as imaginary number.

Input

a1 = 3, b1 = 8
a2 = 5, b2 = 2

Output

Complex number 1: 3 + i8
Complex number 2: 5 + i2
Sum of the complex numbers: 8 + i10

Explanation

(3+i8) + (5+i2) = (3+5) + i(8+2) = 8 + i10

Input

a1 = 5, b1 = 3
a2 = 2, b2 = 2

Output

Complex number 1: 5 + i3
Complex number 2: 2 + i2
Sum of the complex numbers: 7 + i5

Explanation

(5+i3) + (2+i2) = (5+2) + i(3+2) = 7 + i5

## Approach used below is as follows to solve the problem

• Declare a struct for storing the real and imaginary numbers.

• Take the input and add the real numbers and imaginary numbers of all the complex numbers.

## Algorithm

Start
Decalre a struct complexnum with following elements
1. real
2. img
In function complexnum sumcomplex(complexnum a, complexnum b)
Step 1→ Declare a signature struct complexnum c
Step 2→ Set c.real as a.real + b.real
Step 3→ Set c.img as a.img + b.img
Step 4→ Return c
In function int main()
Step 1→ Declare and initialize complexnum a = {1, 2} and b = {4, 5}
Step 2→ Declare and set complexnum c as sumcomplex(a, b)
Step 3→ Print the first complex number
Step 4→ Print the second complex number
Step 5→ Print the sum of both in c.real, c.img
Stop

## Example

#include <stdio.h>
//structure for storing the real and imaginery
//values of complex number
struct complexnum{
int real, img;
};
complexnum sumcomplex(complexnum a, complexnum b){
struct complexnum c;
c.real = a.real + b.real;
c.img = a.img + b.img;
return c;
}
int main(){
struct complexnum a = {1, 2};
struct complexnum b = {4, 5};
struct complexnum c = sumcomplex(a, b);
printf("Complex number 1: %d + i%d\n", a.real, a.img);
printf("Complex number 2: %d + i%d\n", b.real, b.img);
printf("Sum of the complex numbers: %d + i%d\n", c.real, c.img);
return 0;
}

## Output

If run the above code it will generate the following output −

Complex number 1: 1 + i2
Complex number 2: 4 + i5
Sum of the complex numbers: 5 + i7
Published on 13-Aug-2020 08:20:31