Program for Mean Absolute Deviation in C++

Given with an array of natural numbers and the task is to calculate the mean absolute deviation and for that we must require the knowledge of mean, variance and standard deviation.

There are steps that need to be followed for calculating the mean absolute deviation

Calculate the mean
Calculate absolute deviation
Add all the calculated deviations
Apply the formula

Input

arr[] = { 34,21,56,76,45,11}

Output

mean absolute deviation is : 18.5

Input

arr[] = {10, 15, 15, 17, 18, 21}

Output

mean absolute mean absolute deviation is : 2.66

used in the given program is as follows

Input the elements of an array
Calculate the mean of an array
Calculate deviation using formula Sum = Sum + abs(arr[i] - Mean(arr, n))
calculate mean absolute deviation by dividing the total deviation with total number of elements in an array

(abs(arr[0] – mean) + abs(arr[1] – mean) + . . + abs(arr[n-1] – mean) / n

Algorithm

Start
Step 1→ declare function to calculate mean
   float mean(float arr[], int size)
      declare float sum = 0
      Loop For int i = 0 and i < size and i++
         Set sum = sum + arr[i]
      End
      return sum / size
Step 2→ Declare function to calculate deviation
   float deviation(float arr[], int size)
   declare float sum = 0
   Loop For int i = 0 and i < size and i++
      Set sum = sum + abs(arr[i] - mean(arr, size))
   End
   return sum / size
Step 3→ In main()
   Declare float arr[] = { 34,21,56,76,45,11}
   Declare int size = sizeof(arr) / sizeof(arr[0])
   Call deviation(arr, size)
Stop

Example

Live Demo

#include <bits/stdc++.h>
using namespace std;
//calculate mean using mean function
float mean(float arr[], int size){
   float sum = 0;
   for (int i = 0; i < size; i++)
      sum = sum + arr[i];
   return sum / size;
}
//calculate mean deviation
float deviation(float arr[], int size){
   float sum = 0;
   for (int i = 0; i < size; i++)
      sum = sum + abs(arr[i] - mean(arr, size));
   return sum / size;
}
int main(){
   float arr[] = { 34,21,56,76,45,11};
   int size = sizeof(arr) / sizeof(arr[0]);
   cout<<"mean absolute deviation is : "<<deviation(arr, size);
   return 0;
}