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Printing Interesting pattern in C++
This article prints an interesting pattern using C++ programming. Here is the algorithm as following
Algorithm
Step-1 Define the size which will be double automatically Step-2 Print the upper section using a loop Step-3 Print the lower section using a loop
Example
Based on the above algorithm, the following c++ code is carved out as;
#include <iostream>
using namespace std;
int main(){
int n=3;
int i,j;
// This is upper half of pattern
for (i=1; i<=n; i++){
for (j=1; j<=(2*n); j++){
// Left part of pattern
if (i<j)
cout<<" ";
else
cout<<"*";
// Right part of pattern
if (i<=((2*n)-j))
cout<<" ";
else
cout<<"*";
}
cout<<endl;
}
// This is lower half of pattern
for (i=1; i<=n; i++){
for (j=1;j<=(2*n);j++){
// Left part of pattern
if (i>(n-j+1))
cout<<" ";
else
cout<<"*";
// Right part of pattern
if ((i+n)>j)
cout<<" ";
else
cout<<"*";
}
cout<<endl;
}
return 0;
}After compilation of the above code, the interesting pattern will be printed looks like as.
Output
* * * * * * * * * * * * * * * * * * * * * * * *
Updated on: 16-Jan-2020
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