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Print the string after the specified character has occurred given no. of times in C Program
Task is to print the given after the specified character occurrence for given number of times which is specified by the user
Input : string = {“I am harsh vaid “}
Char =’a’
Count =2
Output : rsh vaidIt means user specified character ‘a’ and its occurrence 2 so the output string should be displayed after two occurrences of a.
Algorithm
START Step 1 -> input character in ch(e.g. ‘a’) and count(e.g. 2) as int Step 2 -> declare and initialize n with size of a string by sizeof(string)/sizeof(string[0]) Step 3 - > Loop For i to 0 and i<n and i++ IF count > 0 IF string[i]==ch Count=count-1 End IF Continue End IF Else Print string[i] End Else Step 4 -> End For STOP
Example
#include <stdio.h>
int main(int argc, char const *argv[]) {
char string[] = {"I am Harsh Vaid"};
char ch = 'a';
int i, count = 2;
int n = sizeof(string)/sizeof(string[0]);
for( i = 0; i < n; i++ ) {
if(count>0) {
if(string[i]==ch) {
count--;
}
continue;
}
else
printf("%c", string[i]);
}
return 0;
}Output
If we run above program then it will generate following output
rsh Vaid
Updated on: 08-Aug-2019
622 Views
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