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Print prime numbers from 1 to N in reverse order
Input number n till which prime numbers are calculated and displayed in reverse order
Input : number 30 Output : 29 23 19 17 13 11 7 5 3 2
Algorithm
START Step 1 -> declare variables as n, I, j, flag to 0 as int Step 2 -> input number in n Step 3 -> Loop For from i to n and i>1 and i— Step 3.1 ->. Inner loop for from j to i/2 and j>=1 and j— Statement If %j==0 && j!=1 Set flag=0 Break End IF Else Flag=1 End Else Step 3.2 -> end inner Loop For Step 4 -> statement IF to check flag=1 Print i End IF Step 5 -> End outer For STOP
Example
#include <stdio.h> int main(int argc, char const *argv[]) { int n, i, j, flag=0; printf("Enter a number\n"); scanf("%d", &n); for(i=n; i>1; i--) { for (j = i/2; j >= 1; j--) { if(i%j==0 && j!=1) { flag = 0; break; } else flag = 1; } if(flag == 1) { printf("%d ", i); } } return 0; }
Output
If we run the above program then it will generate the following output
Enter a number 30 29 23 19 17 13 11 7 5 3 2
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