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Print pair with maximum AND value in an array in C Program.
According to the problem we are given an array of n positive integers, we have to find a pair with maximum AND value from the array.
Example
Input: arr[] = { 4, 8, 12, 16 }
Output: pair = 8 12
The maximum and value= 8
Input:arr[] = { 4, 8, 16, 2 }
Output: pair = No possible AND
The maximum and value = 0For finding Maximum AND value is similar to find out Maximum AND value in an array. Program must find out the pair of elements resulting in obtained AND value. For finding the elements, simply traverse the whole array and find the AND value of each element with the obtained maximum AND value (result) and if arr[i] & result == result, that means arr[i] is the element which will generate maximum AND value. Also, in the case if maximum AND value (result) is zero then we should print “Not possible” in that case.
Algorithm
int checkBit(int pattern, int arr[], int n) START STEP 1: DECLARE AND INITIALIZE count AS 0 STEP 2: LOOP FOR i = 0 AND i < n AND i++ IF (pattern & arr[i]) == pattern THEN, INCREMENT count BY 1 STEP 3: RETURN count STOP int maxAND(int arr[], int n) START STEP 1: DECLARE AND INITIALIZE res = 0 AND count STEP 2: LOOP FOR bit = 31 AND bit >= 0 AND bit-- count = GOTO FUNCTION checkBit(res | (1 << bit), arr,n) IF count >= 2 THEN, res |= (1 << bit); END IF IF res == 0 PRINT "no possible AND” ELSE PRINT "Pair with maximum AND= " count = 0; LOOP FOR int i = 0 AND i < n && count < 2 AND i++ IF (arr[i] & res) == res THEN, INCREMENT count BY 1 PRINT arr[i] END IF END FOR END FOR RETURN res STOP
Example
#include <stdio.h>
int checkBit(int pattern, int arr[], int n){
int count = 0;
for (int i = 0; i < n; i++)
if ((pattern & arr[i]) == pattern)
count++;
return count;
}
// Function for finding maximum AND value pair
int maxAND(int arr[], int n){
int res = 0, count;
for (int bit = 31; bit >= 0; bit--) {
count = checkBit(res | (1 << bit), arr, n);
if (count >= 2)
res |= (1 << bit);
}
if (res == 0) //if there is no pair available
printf("no possible and
");
else { //Printing the pair available
printf("Pair with maximum AND= ");
count = 0;
for (int i = 0; i < n && count < 2; i++) {
// incremnent count value after
// printing element
if ((arr[i] & res) == res) {
count++;
printf("%d ", arr[i]);
}
}
}
return res;
}
int main(int argc, char const *argv[]){
int arr[] = {5, 6, 2, 8, 9, 12};
int n = sizeof(arr)/sizeof(arr[0]);
int ma = maxAND(arr, n);
printf("
The maximum AND value= %d ", ma);
return 0;
}Output
If we run the above program then it will generate the following output −
pair = 8 9 The maximum and value= 8
Updated on: 22-Aug-2019
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